[Resolução] III.6.10b

Disciplina de Cálculo IV do ICMC
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Zesim
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[Resolução] III.6.10b

Post by Zesim »

\(a_n=\frac{1}{\pi }\int_{\pi}^{-\pi}\left | x \right |cosnxdx

= \frac{2}{n^2\pi}cos(nx)|^\pi _0 =
\left\{\begin{matrix}
-\frac{4}{n^2\pi}&impar \\
0&par
\end{matrix}\right.
\\
|x|=\frac{\pi^2}{2}-\frac{4}{\pi} \sum_{n=1}^{\infty}\frac{cosnx}{n^2}=\frac{\pi^2}{2}-\frac{4}{\pi} \sum_{n=1}^{\infty}\frac{cos(2n-1)x}{(2n-1)^2}
\\
0 = \frac{\pi}{2}-\frac{4}{\pi}\sum_{n=1}^{\infty}\frac{1}{(2n-1)^2}
\\
\sum_{n=1}^{\infty}\frac{1}{(2n-1)^2} = \frac{\pi^2}{8}\)
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