Cálculo

\[\begin{array}{rcl} \lim\limits_{x \to +\infty} \frac{\sqrt{x + 1}}{\sqrt{x}} & = & \lim\limits_{x \to +\infty} \frac{\sqrt{x}\sqrt{1 + \frac{1}{x}}}{\sqrt{x}}\\ & = & 1 \end{array}\]